for (int i = n - 1; i 0; i--) {
Phil Collins performed seated on his last tour, and recently revealed he has a 24-hour live-in nurse
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需求遍历弹出条件栈类型下一个更大元素的索引倒序栈顶 ≤ 当前 → 弹出严格单调递减栈下一个更大或相等元素的索引倒序栈顶 < 当前 → 弹出非严格单调递减栈下一个更小元素的索引倒序栈顶 ≥ 当前 → 弹出严格单调递增栈下一个更小或相等元素的索引倒序栈顶 当前 → 弹出非严格单调递增栈上一个更大元素的索引正序栈顶 ≤ 当前 → 弹出严格单调递减栈上一个更大或相等元素的索引正序栈顶 < 当前 → 弹出非严格单调递减栈上一个更小元素的索引正序栈顶 ≥ 当前 → 弹出严格单调递增栈上一个更小或相等元素的索引正序栈顶 当前 → 弹出非严格单调递增栈
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Fast forward a year: they get a new phone and set up the messaging app. They aren’t prompted to use a passkey because one no longer exists in their credential manager. Instead, they use phone number verification to recover their account. They are then guided through the “restore backup” flow and prompted for their passkey.